## Algebra and Trigonometry 10th Edition

Domain: $x\gt3$ or $(3,∞)$ x-intercept: $(4,0)$ $x=3$ is the vertical asymptote.
$h(x)=\log_4(x-3)$ Domain: $x-3\gt0$ $x\gt3$ or $(3,∞)$ x-intercept: $h(x)=\log_4(x-3)=0$ $4^0=x-3$ $x-3=1$ $x=4~~$ So, the x-intercept point is $(4,0)$ $\log_ax→-∞$ when $x→0^+$. So, we have that: $\log_4(x-3)→-∞$ when $x-3→0^+$ $\log_4(x-3)→-∞$ when $x→3^+$. Then $x=3$ is the vertical asymptote.