Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 4 - Review Exercises - Page 354: 63


$(x -4)^2=-8(y-2)$

Work Step by Step

We are given that the focus is below the given vertex; thus, $ p$ is the negative of the distance between the two points. So, $p=-|2-0|=-2$ The vertex and focus have the same x-coordinate, so the parabola must have a vertical axis. Now, we will write the equation for the parabola that has a vertical axis using the vertex and $p$. $(x-h)^2=4p(y-k)$ $\implies (x -4)^2=-8(y-2)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.