Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 4 - Review Exercises - Page 354: 85

Answer

$8 \sqrt 6$

Work Step by Step

$(x-h)^2=4p(y-k)$ or, $(4-0)^2=4p(10-12)$ or, $p=-2$ Now, $x^2=-8(y-12)$ or, $x^2=-8(0-12)$ $x=4 \sqrt 6$ The width at ground level is $2x= 8 \sqrt 6$
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