Answer
$180.278$
Work Step by Step
The distance from the water fountain can be computed as:
$d=\sqrt {(-100-0)^2+(150-0)^2}=\sqrt {32500}$
or, $d=50\sqrt {13}$
or, $d \approx 180.278$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 4 - Review Exercises - Page 354: 87c
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