## Algebra and Trigonometry 10th Edition

$34$
The parabola has a vertical axis. We write the equation of the parabola as follows: $(x-h)^2=4p(y-k)$ $6^2=4p(14-16)$ $\implies p=\dfrac{-9}{2}$ and $x^2=4(-9/2) (y-16) \implies x^2=-18(y-16)$ Consider $y=0$ Now, we have: $x^2=-18(0-16) \implies x^2=-18 \times -16$ or, $x=\sqrt {288}$ Now, $2x=2\sqrt {288}=34$