Answer
All real numbers and $y=-1$
Work Step by Step
Domain: $3+x^2 \ne 0$
So, $x^2 \ne -3$
This means that the domain is all real numbers.
There are no vertical asymptotes that occur at the zeros of the denominator.
Find the horizontal asymptotes. The degree of the numerator is equal to the degree of the denominator.
$y=\dfrac{-1}{1}=-1$
