Answer
$x \approx 12.49$ and $y=6.24$
Work Step by Step
We have: $36=(y-2(1))(x-2(2))$
$\implies 36=(x-4)(y-2)$
So, $y=\dfrac{36}{x-4}+2$
Now, $y=\dfrac{2x+28}{x-4}$
or, $xy=2x+4y+8$
or, $xy=2x+4(\dfrac{2x+28}{x-4}) +8$
Thus, $A=xy=\dfrac{2(x^3+4x+40)}{x-4}$
So, $x \approx 12.49$ and $y=\dfrac{2(12.49)+28}{12.49-4}=6.24$
