Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 4 - 4.4 - Translations of Conics - 4.4 Exercises - Page 348: 43a


$x^2 =- 49 (y- 100)$

Work Step by Step

We are given that $v =28 \ ft/s$ and $s=100 \ ft$. Substitute this in the model: $x^2 =(-\dfrac{v^2}{16}) (y- s)$ $x^2 =[-\dfrac{(28)^2}{16}] (y- 100)$ Our answer is: $x^2 =- 49 (y- 100)$
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