Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 4 - 4.4 - Translations of Conics - 4.4 Exercises - Page 348: 35

Answer

$(y-2)^2=-8(x-3)$

Work Step by Step

We are given that the focus is to the left of the given vertex, thus, $ p$ is the negative of the distance between the two points. So, $p=-|3-1|=-2$ Since the vertex and focus have the same y-coordinate, the parabola must have a horizontal axis. Now, we will write the equation for the parabola that has a horizontal axis using the vertex and p. $(y-k)^2=4p(x-h)$ $\implies (y-2)^2=-8(x-3)$
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