## Algebra and Trigonometry 10th Edition

$(y-2)^2=-8(x-3)$
We are given that the focus is to the left of the given vertex, thus, $p$ is the negative of the distance between the two points. So, $p=-|3-1|=-2$ Since the vertex and focus have the same y-coordinate, the parabola must have a horizontal axis. Now, we will write the equation for the parabola that has a horizontal axis using the vertex and p. $(y-k)^2=4p(x-h)$ $\implies (y-2)^2=-8(x-3)$