## Algebra and Trigonometry 10th Edition

$(x-0)^2=8(y-4)$
We are given that the directrix is below the given vertex, thus, $p$ is the distance between the two points. So, $p=4-2=2$ Since the directrix is horizontal, the parabola must have a vertical axis. Now, we will write the equation for the parabola that has a vertical axis using the vertex and $p$. $(x-h)^2=4p(y-k)$ $\implies (x-0)^2=8(y-4)$