Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 4 - 4.3 - Conics - 4.3 Exercises - Page 339: 80

Answer

Vertices: $(0,±\frac{1}{2})$ Asymptotes: $y=±\frac{1}{2}x~~$ (Black Lines)
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Work Step by Step

Standard form when transverse axis is vertical: $\frac{y^2}{a^2}-\frac{x^2}{b^2}=1$ $4y^2-x^2=225$ $\frac{y^2}{\frac{1}{4}}-\frac{x^2}{1}=1$ $a^2=\frac{1}{4}$ $a=\frac{1}{2}$ $b^2=1$ $b=1$ Vertices when transverse axis is vertical: $(0,±a)=(0,±\frac{1}{2})$ Asymptotes when transverse axis is vertical: $y=±\frac{a}{b}x$ $y=±\frac{\frac{1}{2}}{1}x=±\frac{1}{2}x$
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