Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 4 - 4.3 - Conics - 4.3 Exercises - Page 339: 64



Work Step by Step

Transverse axis is horizontal. $(±a,0)=(±4,0)$ $a=4$ $(±c,0)=(±,0)$ $c=5$ $b^2=c^2-a^2=25-16=9$ $b=3$ Standard form when transverse axis is horizontal: $\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$ $\frac{x^2}{4^2}-\frac{y^2}{3^2}=1$ $\frac{x^2}{16}-\frac{y^2}{9}=1$
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