Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 4 - 4.3 - Conics - 4.3 Exercises - Page 339: 77

Answer

Vertices: $(0,±3)$ Asymptotes: $y=±\frac{3}{5}x$
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Work Step by Step

Standard form when transverse axis is vertical: $\frac{y^2}{a^2}-\frac{x^2}{b^2}=1$ $25y^2-9x^2=225$ $\frac{y^2}{9}-\frac{x^2}{25}=1$ $a^2=9$ $a=3$ $b^2=25$ $b=5$ Vertices when transverse axis is vertical: $(0,±a)=(0,±3)$ Asymptotes when transverse axis is vertical: $y=±\frac{a}{b}x$ $y=±\frac{3}{5}x$
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