Answer
Vertices: $(±5,0)$
Eccentricity: $e=\frac{3}{5}$
Work Step by Step
$\frac{x^2}{25}+\frac{y^2}{16}=1$
$\frac{x^2}{5^2}+\frac{y^2}{4^2}=1$
The major axis is horizontal.
Standard form when major axis is horizontal:
$\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$
So: $a=5$ and $b=4$
$a^2=b^2+c^2$
$c^2=a^2-b^2=25-16=9$
$c=3$
$e=\frac{c}{a}=\frac{3}{5}$
Vertices when major axis is horizontal:
$(±a,0)=(±5,0)$
