Answer
$x^2+\frac{y^2}{4}=1$
Work Step by Step
Major axis is vertical.
Vertices:
$(0,2)=(0,a)$
$(0,-2)=(0,-a)$
$(1,0)=(b,0)$
$(-1,0)=(-b,0)$
That is, $a=2$ and $b=1$
Standard form when major axis is vertical:
$\frac{x^2}{b^2}+\frac{y^2}{a^2}=1$
$\frac{x^2}{1^2}+\frac{y^2}{2^2}=1$
$x^2+\frac{y^2}{4}=1$
