## Algebra and Trigonometry 10th Edition

$x^2+\frac{y^2}{4}=1$
Major axis is vertical. Vertices: $(0,2)=(0,a)$ $(0,-2)=(0,-a)$ $(1,0)=(b,0)$ $(-1,0)=(-b,0)$ That is, $a=2$ and $b=1$ Standard form when major axis is vertical: $\frac{x^2}{b^2}+\frac{y^2}{a^2}=1$ $\frac{x^2}{1^2}+\frac{y^2}{2^2}=1$ $x^2+\frac{y^2}{4}=1$