Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 3 - P.S. Problem Solving - Page 308: 13


$2in,2in, 5in$

Work Step by Step

Let $x$ be the length of the base's side. Then our equation for the volume is: $x^2(x+3)=20\\x^3+3x^2-20=0\\(x-2)(x^2+5x+10)=0.$ $x^2+5x+10$ cannot be $0$ because its determinant is $0$, thus the only solution of the equation is $x=2$. Thus the dimensions are $2in,2in, 5in$
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