Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 3 - P.S. Problem Solving - Page 308: 12c

Answer

$A(0)=796~cm^2$ If you want the maximum area, use all the wire to form the circle.

Work Step by Step

$A=\frac{(4+\pi)x^2-800x+40000}{16\pi}$ The parabola opens upwards. The maximum area must be one of the extremes. The vertex would give us the minimum area. $A(0)=\frac{40000}{16\pi}=\frac{2500}{\pi}\approx796~cm^2$ $A(100)=\frac{(4+\pi)10000-80000+40000}{16\pi}=\frac{(4+\pi)625-2500}{\pi}=625~cm^2$
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