## Algebra and Trigonometry 10th Edition

The formula: $m=\frac{f(2+h)-4}{h}$ At $h=-1$: $\frac{(2+(-1))^2-4}{-1}=\frac{1-4}{-1}=\frac{-3}{-1}=3$ At $h=1$: $\frac{(2+(1))^2-4}{1}=\frac{9-4}{1}=\frac{5}{1}=5$ At $h=0.1$: $\frac{(2+(0.1))^2-4}{0.1}=\frac{4.41-4}{0.1}=\frac{0.41}{0.1}=4.1$ These values match the ones found in the earlier parts.