## Algebra and Trigonometry 10th Edition

Area = 64-2$x^2$, $0 \leq x \leq 4$
Area of the square = 8*8 = 64 Area of each isosceles triangle = $x^2$/2 Hence area of the resulting figure = area of the square - 4(area of the triangle) = 64 - 4($x^2$)/2 = 64-2$x^2$ For data to be valid, $2x \leq 8$ ,hence $x \leq 4$ Also x must be non-negative. Hence, $0 \leq x \leq 4$