## Algebra and Trigonometry 10th Edition

$s(t) = 20t^\frac{3}{2}$ Average speed of the car from t=0 to t=9. $(s(9)-s(0))/(9-0)=(20(9)^\frac{3}{2}-20(0)^\frac{3}{2})/(9-0)=540/9=60 feet/sec$