## Algebra and Trigonometry 10th Edition

We are given the function: $f(x)=\sqrt[3]{x-4}$ Graph the function: The graph shows that the function is not symmetric about any axis; therefore it is neither even nor odd. Check the result algebraically: $f(-x)=\sqrt[3]{-x-4}=-\sqrt[3]{x+4}$ $f(-x)\not=-f(x)$ $f(-x)\not=f(x)$ So the function is neither even nor odd.