Answer
Neither even nor odd.
Work Step by Step
We are given the function:
$f(x)=\sqrt[3]{x-4}$
Graph the function:
The graph shows that the function is not symmetric about any axis; therefore it is neither even nor odd.
Check the result algebraically:
$f(-x)=\sqrt[3]{-x-4}=-\sqrt[3]{x+4}$
$f(-x)\not=-f(x)$
$f(-x)\not=f(x)$
So the function is neither even nor odd.
