## Algebra and Trigonometry 10th Edition

Published by Cengage Learning

# Chapter 2 - 2.2 - Functions - 2.2 Exercises - Page 184: 65

#### Answer

2008: $67.36\%$ 2009: $70.13\%$ 2010: $72.90\%$ 2011: $75.67\%$ 2012: $79.30\%$ 2013: $81.25\%$ 2014: $82.20\%$

#### Work Step by Step

We are given the function: $p(t)=\begin{cases} 2.77t+45.2,8\leq t\leq 11\\ 1.95t+55.9,12\leq t\leq 14 \end{cases}$ As $t=8$ corresponds to 2008, it means that $t=9$ corresponds to 2009, $t=10$ to 2010, $t=11$ to 2011, $t=12$ to 2012, $t=13$ to 2013 and $t=14$ to 2014. Compute $p(t)$ for $t=8,9,10,11$: 2008: $p(8)=2.77(8)+45.2=67.36$ 2009: $p(9)=2.77(9)+45.2=70.13$ 2010: $p(10)=2.77(10)+45.2=72.90$ 2011: $p(11)=2.77(11)+45.2=75.67$ Compute $p(t)$ for $t=12,13,14$: 2012: $p(12)=1.95(12)+55.9=79.30$ 2013: $p(13)=1.95(13)+55.9=81.25$ 2014: $p(14)=1.95(14)+55.9=83.20$

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