## Algebra and Trigonometry 10th Edition

Area = $\frac{a^2}{2(a-2)}$, a>2
Plug in the given point to solve for b, 1= -2b/a + b a = -2b + ab a = b(a-2) b = a/(a-2) Area of the triangle is A = ab/2 = $\frac{a^2}{2(a-2)}$ Area must be positive and the denominator must be non zero, hence a-2>0 giving a>2.