Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 2 - 2.2 - Functions - 2.2 Exercises - Page 184: 63


Area = $\frac{a^2}{2(a-2)}$, a>2

Work Step by Step

Plug in the given point to solve for b, 1= -2b/a + b a = -2b + ab a = b(a-2) b = a/(a-2) Area of the triangle is A = ab/2 = $\frac{a^2}{2(a-2)}$ Area must be positive and the denominator must be non zero, hence a-2>0 giving a>2.
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