# Chapter 2 - 2.2 - Functions - 2.2 Exercises - Page 184: 64

A = $2x(\sqrt {36-x^2}), 0\leq x \leq 6$

#### Work Step by Step

Area $A = 2xy = 2x(\sqrt {36-x^2})$ (Use the diagram and the given function to find the area of the rectangle.) $0\leq x \leq 6$ for the expression under the square root to be non-negative.

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