Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 2 - 2.1 - Linear Equations in Two Variables - 2.1 Exercises - Page 172: 113

Answer

y=-20x/3 -139/12

Work Step by Step

Given points (3,5/2) and (-7,1) Their midpoint = ((3-7)/2, (5/2+1)/2) = (-2,7/4) Find the slope of the line passing through the given points (m) : $m=\frac{y_2-y_1}{x_2-x_1}=3/20$ Slope of a line perpendicular to this line = -20/3 (negative reciprocal) Use the slope and a point to find the line such that (x, y) is equidistant from the two points. y = mx+b 7/4 = -20/3(-2)+b b = -139/12 y=-20x/3 -139/12
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.