## Algebra and Trigonometry 10th Edition

Given points (3,5/2) and (-7,1) Their midpoint = ((3-7)/2, (5/2+1)/2) = (-2,7/4) Find the slope of the line passing through the given points (m) : $m=\frac{y_2-y_1}{x_2-x_1}=3/20$ Slope of a line perpendicular to this line = -20/3 (negative reciprocal) Use the slope and a point to find the line such that (x, y) is equidistant from the two points. y = mx+b 7/4 = -20/3(-2)+b b = -139/12 y=-20x/3 -139/12