## Algebra and Trigonometry 10th Edition

Given points (6,5) and (1,-8) Their midpoint = ((6+1)/2, (5-8)/2) = (7/2,-3/2) Find the slope of line passing through the given points (m) : $m=\frac{y_2-y_1}{x_2-x_1}=13/5$ Slope of a line perpendicular to this line = -5/13 (negative reciprocal). Use the slope and a point to find the line such that (x, y) is equidistant from the two points. y = mx+b -3/2 = -5/13(7/2)+b b = -2/13 y=-5x/13 -2/13