## Algebra and Trigonometry 10th Edition

Given points (4,-1) and (-2,3) Their midpoint = ((4+(-2))/2, (-1+3)/2) = (1,1) Find the slope of the line passing through the given points (m) : $m=\frac{y_2-y_1}{x_2-x_1}=(-1-3)/(4-(-2))=-2/3$ Slope of a line perpendicular to this line = 3/2 (negative reciprocal) Use the slope and point to find the line such that (x, y) is equidistant from the two points. y = mx+b 1 = 3/2(1)+b b = -1/2 y=3x/2 - 1/2