Answer
$P(getting~four~5's)=\frac{1}{1296}\approx0.000772$
Work Step by Step
For each die (the sample space: [1,2,3,4,5,6]):
$P(getting~a~5)=\frac{N(5)}{N(S)}=\frac{1}{6}$
If a die is tossed four times:
$P(getting~four~5's)=(\frac{1}{6})^4=\frac{1}{1296}\approx0.000772$
