## Algebra and Trigonometry 10th Edition

$P(correct~order)=\frac{1}{120}\approx0.00833$
First let's find the number of ways the child can organize the books: $n!=5!=5\times4\times3\times2\times1=120$ But, there is only one correct way to organize the books: $P(correct~order)=\frac{1}{120}\approx0.00833$