## Algebra and Trigonometry 10th Edition

$P(at~least~one~tail)=\frac{31}{32}$
Let's find the probability of getting no tail: $P(no~tail~five~times)=P(not~a~tail)^5=(\frac{1}{2})^5=\frac{1}{32}$ The event "getting at least one tail" is the complement of the event "getting no tail": $P(at~least~one~tail)=1-P(no~tail~five~times)=1-\frac{1}{32}=\frac{31}{32}$