Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.3 - Geometric Sequences and Series - 11.3 Exercises - Page 796: 74



Work Step by Step

$\displaystyle \sum_{n=0}^{∞}4(0.2)^n=4(0.2)^0+4(0.2)^1+4(0.2)^2+...$ $a_1=4(0.2)^0=4$ $r=\frac{a_2}{a_1}=\frac{4(0.2)^1}{4(0.2)^0}=0.2$ $S=\frac{a_1}{1-r}=\frac{4}{1-0.2}=\frac{4}{0.8}=5$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.