Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.3 - Geometric Sequences and Series - 11.3 Exercises - Page 796: 65


$10+30+90+...+7290=\displaystyle \sum_{n=1}^{7}10(3)^{n-1}$

Work Step by Step

$7290=10(729)=10(3)^6$ $10+30+90+...+7290=10(3)^0+10(3)^1+10(3)^2+...10(3)^6=\displaystyle \sum_{n=1}^{7}10(3)^{n-1}$
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