Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.3 - Geometric Sequences and Series - 11.3 Exercises - Page 796: 68


$32+24+18+13.5+10.125=\displaystyle \sum_{n=1}^{5}32(0.75)^{n-1}$

Work Step by Step

$10.125=32(0.75)^4$ $32+24+18+13.5+10.125=32(0.75)^0+32(0.75)^1+32(0.75)^2+32(0.75)^3+32(0.75)^4=\displaystyle \sum_{n=1}^{5}32(0.75)^{n-1}$
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