Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 10 - Review Exercises - Page 763: 102

Answer

$-4$

Work Step by Step

The general form of a matrix of order $ 2 \times 2$ is: $det \ A=\begin{bmatrix} p & q \\ r & s\end{bmatrix}=ps-qr$ Since Column-1 has the most zeroes, we choose Column-1. It has sign array $(+,+)$ as we go down. Now, $det \ A =0+0+(-1) \begin{bmatrix} 1 & -2 \\ 1 & 2 \end{bmatrix}=-1(2+2)=-4$
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