## Algebra and Trigonometry 10th Edition

Published by Cengage Learning

# Chapter 10 - Review Exercises - Page 763: 101

#### Answer

$-6$

#### Work Step by Step

The general form of a matrix of order $2 \times 2$ is: $det \ A=\begin{bmatrix} p & q \\ r & s\end{bmatrix}=ps-qr$ Since Row-1 has the most zeroes, we choose $R_1$. It has sign array $(+,+)$ as we go to the right. Now, $det \ A =-2 \begin{bmatrix} -1 & 0 \\ 1 & -3 \end{bmatrix}-0+0=-2(3-0)=-6$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.