#### Answer

No Solution.

#### Work Step by Step

We write the system of equations as follows:
$-x+2y=3 \\ 2x-4y =6$
We divide $R_1$ by $-1$ .
The new system of equations is:
$x-2y=-3 \\ 2x-4y =6$
We subtract $R_2$ by $2R_1$, giving:
$x-2y=-3 \\ 0 =12$
Thus, no solution exists.