## Algebra and Trigonometry 10th Edition

We write the system of equations as follows: $-x+2y=3 \\ 2x-4y =6$ We divide $R_1$ by $-1$ . The new system of equations is: $x-2y=-3 \\ 2x-4y =6$ We subtract $R_2$ by $2R_1$, giving: $x-2y=-3 \\ 0 =12$ Thus, no solution exists.