## Algebra and Trigonometry 10th Edition

$x=-50, y=-6, z=1$
Write the system of equations corresponding to the augmented matrix as follows: $x-8y=-2 \\ y-z =-7 \\ z=1$ Substitute the value of $z=1$ in $y-z=-7$ to obtain: $y-1=-7 \implies y=-6$ Now, $x-8(-6)=-2 \implies x=-50$ Therefore, $x=-50, y=-6, z=1$