## Algebra and Trigonometry 10th Edition

$x=0.0750, y=0.08$
We write the system of equations as follows: $0.2x -0.1y=0.007 \\ 0.4x-0.5y =-0.01$ We divide the $R_1$ by $2$ . The new system of equations is: $x -0.5y=0.0350 \\ 0.4x-0.5y =-0.01$ After solving the two equations, we have $y=0.08$ Now, $0.2x -0.1(0.08)=0.007 \implies x=0.0750$ Therefore, $x=0.0750, y=0.08$