Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - Review Exercises - Page 152: 37

Answer

x-intercept: $(\frac{4}{3},0)$ y-intercept: $(0,\frac{2}{3})$

Work Step by Step

$y=-\frac{1}{2}x+\frac{2}{3}$ Make $y=0$ to find the x-intercept: $0=-\frac{1}{2}x+\frac{2}{3}$ $\frac{1}{2}x=\frac{2}{3}$ $x=\frac{2}{3}·2=\frac{4}{3}$ We have the point: $(\frac{4}{3},0)$ Make $x=0$ to find the y-intercept: $y=-\frac{1}{2}(0)+\frac{2}{3}=0+\frac{2}{3}=\frac{2}{3}$ We have the point: $(0,\frac{2}{3})$
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