Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - Review Exercises - Page 152: 31

Answer

$x=13$

Work Step by Step

Multiply both sides by $x-5$: $$3(x-5)+\frac{2}{x-5}(x-5)=\frac{2x}{x-5}(x-5)$$ $$3x-15+2=2x$$ $$3x-2x-15+2=0$$ $$x-13=0$$ $$x=13$$ Checking: $$3+\frac{2}{13-5}\stackrel{?}{=}\frac{2(13)}{13-5}$$ $$3+\frac{1}{4}\stackrel{?}{=}\frac{26}{8}$$ $$\frac{12+1}{4}\stackrel{?}{=}\frac{13}{4}$$ $$\frac{13}{4}=\frac{13}{4}~True$$ Thus, the solution is $x=13$.
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