Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - Review Exercises - Page 152: 28



Work Step by Step

$7(x-4)=1-(x+9)$ $7x-28=1-x-9$ $7x-28=-x-8$ $7x+x=-8+28$ $8x=20$ $x=\frac{20}{8}=\frac{5}{2}$ Check the solution: $7(\frac{5}{2}-4)=1-(\frac{5}{2}+9)$ $7(-\frac{3}{2})=1-\frac{23}{2}$ $-\frac{21}{2}=-\frac{21}{2}$
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