Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - Chapter Test - Page 156: 23


(a=80 and b=20) or (a=20 and b=80)

Work Step by Step

Area of the circle = $\pi r^2=\pi (40)^2=1600\pi$ A = $\pi ab= \pi a(100-a)$ (area of the ellipse given a+b=100) $1600 \pi = \pi a(100-a)$ 1600 = a(100-a) $a^2-100a+1600=0$ (a-80)(a-20)=0 a = 80 giving b=20 or a=20 giving b=80
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