$+\sqrt 2, -\sqrt2, +\sqrt 3i, -\sqrt3i$
Work Step by Step
$x^4+x^2-6=0$ $(x^2+3)(x^2-2)=0$ Either $x^2+3=0$ giving $x = +\sqrt 3i, -\sqrt3i$ or $x^2-2=0$ giving $x = +\sqrt 2, -\sqrt2$
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