Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - Chapter Test - Page 156: 19


Solutions: $x=\frac{3}{2}+\frac{1}{2}i$ $x=\frac{3}{2}-\frac{1}{2}i$

Work Step by Step

$2x^2-6x+=5~~$ ($a=2,b=-6,c=5$): $x=\frac{-b±\sqrt {b^2-4ac}}{2a}=\frac{-(-6)±\sqrt {(-6)^2-4(2)(5)}}{2(2)}=\frac{6±\sqrt {-4}}{4}=\frac{6±2i}{4}=\frac{3}{2}±\frac{1}{2}i$ $x=\frac{3}{2}+\frac{1}{2}i$ or $x=\frac{3}{2}-\frac{1}{2}i$
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