## Algebra and Trigonometry 10th Edition

$$(\sqrt{45}-\sqrt{5})i$$
We know that $i=\sqrt{-1}$ and that $i^2=-1$. We also know that standard form is $a\pm bi$, where a and b are real numbers. Thus, simplifying the equation, we find: $$\sqrt{45}i-\sqrt{5}i \\ (\sqrt{45}-\sqrt{5})i$$ $$(3\sqrt{5}-\sqrt{5})i$$ $$(2\sqrt{5})i$$