## Algebra and Trigonometry 10th Edition

Published by Cengage Learning

# Chapter 1 - 1.5 - Complex Numbers - 1.5 Exercises - Page 119: 61

-15

#### Work Step by Step

We know that $i=\sqrt{-1}$ and that $i^2=-1$. We also know that standard form is $a\pm bi$, where a and b are real numbers. Thus, simplifying the equation, we find: $$\sqrt{15}i\cdot \sqrt{15}i \\ \\ -\sqrt{225} \\ -15$$

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