Answer
$\frac{60}{169}-\frac{25}{169}i$
Work Step by Step
$\frac{5i}{(2+3i)^2}=\frac{5i}{4+12i-9}=\frac{5i}{-5+12i}=\frac{5i}{-5+12i}*\frac{-5-12i}{-5-12i}=\frac{60-25i}{25+144}=$$\frac{60}{169}-\frac{25}{169}i$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.5 - Complex Numbers - 1.5 Exercises - Page 119: 54
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