Algebra: A Combined Approach (4th Edition)

Published by Pearson

Chapter 8 - Section 8.1 - Review of Equations of Lines and Writing Parallel and Perpendicular Lines - Exercise Set - Page 573: 49

Answer

y=-$\frac{1}{2}$x+1 x+2y=2

Work Step by Step

2x+4y=9 4y=-2x+9 y=$\frac{-2}{4}$x+$\frac{9}{4}$ y=$\frac{-1}{2}$x+$\frac{9}{4}$ slope -$\frac{1}{2}$ parallel slope -$\frac{1}{2}$,through (6;-2) y=mx+b -2=$\frac{-1}{2}$6+b -2=-3+b 1=b y=mx+b y=-$\frac{1}{2}$x+1 2y=-x+2 x+2y=2

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