Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 8 - Section 8.1 - Review of Equations of Lines and Writing Parallel and Perpendicular Lines - Exercise Set: 40

Answer

y=-$\frac{1}{2}$x+10

Work Step by Step

through (2;9) ,(8;6) m=$\frac{6-9}{8-2}$=$\frac{-3}{6}$=-$\frac{1}{2}$ y-$y_{1}$=m(x-$x_{1}$) through (2;9) y-9=-$\frac{1}{2}$(x-2) y-9=-$\frac{1}{2}$x+1 y=-$\frac{1}{2}$x+10
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