Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 8 - Section 8.1 - Review of Equations of Lines and Writing Parallel and Perpendicular Lines - Exercise Set - Page 573: 36

Answer

y=$\frac{1}{5}$x-$\frac{17}{5}$

Work Step by Step

x-5y=10 -5y=-x+10 y=$\frac{-x+10}{-5}$ y=$\frac{-1}{-5}$x+$\frac{10}{-5}$ y=$\frac{1}{5}$x-2 slope is $\frac{1}{5}$ Line parallel, slope is $\frac{1}{5}$ through (2;-3) y=mx+b -3=2$\frac{1}{5}$+b -3=$\frac{2}{5}$+b $\frac{-15}{5}$-$\frac{2}{5}$=b -$\frac{17}{5}$=b y=mx+b y=$\frac{1}{5}$x-$\frac{17}{5}$
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